Ln(x^2-1/ x^3) Help please.?

razerbee

From: US
Posts: 6
Votes: 18
Use the properties of logarithms to write the expression as a sum, difference, and/or constant multiple of logarithms.

 

Answer No.1

SuperTeacher25

From: US
Posts: 46
Votes: 92
Ln [(x^2 -1)/(x^3)] = ln(x^2 -1) - 3 ln(x)

Answer No.2

DedicatedKnowledge9

From: US
Posts: 17
Votes: 51
Ln( (x+1)(x-1)/(x * x * x) ) => ln(x+1) + ln(x-1) - 3lnx Hope my answer helps...

Answer No.3

Anonymous

From: -
Posts: -
Votes: -
In [(x^2 -1))/(x^3)] = In(x^2 - 1) - In (x^3)

Answer No.4

Anonymous

From: -
Posts: -
Votes: -
Ln(x^2-1/ x^3) =ln(x^2-1)-ln( x^3)In(x^2-1) - 3 In(x)

Answer No.5

Anonymous

From: -
Posts: -
Votes: -
Ln(x^2-1/ x^3) =ln(x^2-1)-ln( x^3)In(x^2-1) - 3 In(x)

Your Comment/Solution

Post As: Anonymous [Change]
Enter