Integrate this function?

DrTeacher5

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Votes: 20
How do you integrate: 1/(sqrt(9-x^2))?

 

Answer No.1

Anonymous

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∫dx/√(9 - x^2) let x = 3sin (u) ==> sin(u) = x/3 and u = sin^-1(x/3) dx = 3 cos (u) du now the integral becomes ∫3 cos(u) du /√(9 - 9 sin^2(u)) = ∫3 cos(u) du /3 √(1 - sin^2(u)) = ∫ cos(u) du / √(cos^2(u) = ∫ du u + C substitute u = sin^-1(x/3) sin^-1(x/3) + C

Answer No.2

SigmaMan

From: US
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Votes: 44
Try homework website..

Answer No.3

EliteSupa

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∫dx / √(9-x^2) = (1/3)∫dx / √(1-(x/3)^2) = ∫ 1 / √(1-(x/3)^2) (d(x/3))= arcsin(x/3)+C

Answer No.4

Anonymous

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Answer No.5

Anonymous

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