SigmaMath From: US Posts: 41 Votes: 164 |
Please advise & share with me how to solve this question. Thanks a lot. Find a value for the constant k, if possible, that will make the function continuous everywhere 7x – 2 x≤ 1 f(x) = kx2 x>1 kx2 refers to k square(x). Have a nice day. Thank you. Category Science & Mathematics > Mathematics |

Anonymous From: - Posts: - Votes: - |
K= sqrt(5). Set x = 1 in first equation (because "1" is your break point in the domain). the answer is 5. In order for the function to be continuous after 1, it can't take a "jump" (discontinuity). So the best way to do it is make it equal to 5 for x>1. solve for second equation Kx2 = 5 gives you sqrt(5). sqrt = square root.old do you have get viagra prescription aarp recommended canadian pharmacies viagra pill works canada pharmacies viagra generico como tomar viagra without a doctor prescription best place to buy viagra in sydney viagra without a doctor prescription buy cialis levitra and viagra |

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