∫ Xe-xdx

Anonymous

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∫ xe-xdx

 

Answer No.1

Anonymous

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Well you have to use the rule: ∫ udv = uv - ∫vdu ∫ xe-xdx u=x dv= e-xdx du=dx v= -e-x = -xe-x - ∫ -e-xdx =-xe-x - e-x + C Helpful things: d/dx ex = ex also ∫ exdx = ex

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