What Is The Integral Of 2xe^(x^2)dx With A Range O

Anonymous

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What is the integral of 2xe^(x^2)dx with a range of -1 to 0?

 

Answer No.1

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Of 2xe^(x^2)dx with a range of -1 to 0? x^2 = t at x = -1 t = 1 at x= 0 t = 0 2x dx = dt integrla of e^t dt form 1 to 0 e^t e^1 - e^0 = e - 1 1.71828182845905

Answer No.2

Anonymous

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When you're taking an integral, you get e^(x^2) and from -1 to 0, e^(0 -1) = e^(-1) = 1/e is an answer

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