The Volume Of A Cube Is Decreasing At The Rate Of

SuperBrain1

From: US
Posts: 10
Votes: 20
The volume of a cube is decreasing at the rate of 10m^3/hr. How fast is the total surface area decreasing when the surface area is 54m^2?

 

Answer No.1

DedicatedRoger

From: US
Posts: 33
Votes: 33
--A = 6s^2 V = s^3 A = 54 54 = 6s^2 9 = s^2 3 = s V = s^3 dV/dt = 3s^2 * ds/st dV/dt = -10 -10 = 3 * 3^2 * ds/dt -10 = 27 * ds/dt -10/27 = ds/dt A = 6s^2 dA/dt = 12s * ds/st dA/dt = 12 * 3 * (-10/27) dA/dt = -120 / 9 dA/dt = -40/3

Answer No.2

Anonymous

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Votes: -
Sorry i put wrong answer please donot consider it

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