Anonymous From: - Posts: - Votes: - |
The two equal sides of an isosceles triangle has length 4 meters and makes the the angle θ between them. If θ increases at the rate of 2 degrees per second, how fast is the area of the triangle changing when θ is 30 degrees? |

Anonymous From: - Posts: - Votes: - |
As we know area of the triangle = 1/2 ab sinθ a and b are of 4 meters so A = 8sinθ dA/dt = 8cosθ dθ/dt as it is given dθ/dt = 2degree/second and converting them to radians u will get = 2*π/180 rad/sec dA/dt = 8cos30 * 2π/180 = 0.242 m2/s |

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