LovelyBob From: US Posts: 24 Votes: 24 |
The percent of mothers who work outside the home and have children younger than age 6 yr is approximated by the function P(t)=33.55 (t+5)0.2 where t is measured in years, with t=0 corresponding to the beginning of 1980. Compute P’’(18) a. P’’(18)=-0.032734% per year in the second year b. P’’(18)=-0.027556% per year in the second year c. P’’(18)=-0.020688% per year in the second year d. P’’(18)=-0.022378% per year in the second year e. P’’(18)=-0.018998% per year in the second year |

Anonymous From: - Posts: - Votes: - |
I assume you know the basic formulas for derivatives. Well there is one formula I think is a bit hard to understand so I will type it below: (d/dx)(f(x)^n) = n f(x)^(n-1) f'(x) (d/dt)(33.55(t+5)^0.2) = 33.55 (d/dt)[(t+5)^0.2] = 33.55(0.2)(t+5)^(-0.8) = 6.71(t+5)^(-0.8) Now find the second derivative of f'(x) = 6.71(t+5)^(-0.8). f''(x) = 6.71(-0.8)(t+5)^(-1.8) = -5.368(t+5)^(-1.8) f''(18) = -5.368(18+5)^(-1.8) = -0.018998% per year in the second year which is e. PLEASE RATE LIFESAVER if this helps. THANKS. |

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