The Following Five Points Lie On A Function (1,20)

Anonymous

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The following five points lie on a function (1,20) , (2,4), (5,3), (6,2), (10,1) . FIND AN EQUATION THAT PASSES THROUGH THESE POINTS AND HAS THE FOLLOWING FEATURES: -There are three inflection points -There is at least one local maximum -There is at least one local minimum -At least one critical point is not at a given point -The curve is continuous and differentiable throughout -The equation is not a single polynomial, but must be a piesewise defined function There are many possibilities that meet this criteria. Prove that your answer function does so. Please solve in terms of the AB CALCULUS course !!!

 

Answer No.1

Anonymous

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Assume that equation is x5+ax4+bx3+cx2+dx+e=0 There are three inflection points , hence f"(x)=0 will be three real solution. from here put all the condition and get your answer

Answer No.2

MisterAsian2

From: US
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Assume that equation is x5+ax4+bx3+cx2+dx+e=0 There are three inflection points , hence f"(x)=0 will be three real solution. from here put all the condition and get your answer

Answer No.3

BabyGenius

From: US
Posts: 6
Votes: 18
Y = x5+ax4+bx3+cx2+dx+e CONDITIONS: a. 1+a+b+c+d+e = 20 => a+b+c+d+e = 19 b. 32+16a+8b+4c+2d+e= 4 =>16a+8b+4c+2d+e= -28 c. 3125 + 625a +125 b+ 25c+ 5d +e = 3 d. 7776 + 1296 a + 216b + 36c+ 6d +e = 2 solve to get the answer.

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