Suppose Y Is A Function Of X, F(x,y) = 0, And Fy D

EliteHead89

From: US
Posts: 18
Votes: 18
Suppose y is a function of x, F(x,y) = 0, and Fy does not = 0. Show that dy/dx = - Fx/Fy

 

Answer No.1

iGenius

From: US
Posts: 3
Votes: 12
F(x,y) = 0 --> dF=0--> Fxdx+Fydy=0 --> Fxdx=-Fydy --> (dy/dx)=-Fx/Fy

Answer No.2

Anonymous

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Votes: -
F(x,y) = 0 dF = 0 Fx dx + Fy dy = 0 Fxdx = - Fydy Since,Fy != 0 (dy/dx)=-Fx/Fy Hence,proved

Answer No.3

sam mayo

From: US
Posts: 15
Votes: 60
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ∴ 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy

Answer No.4

Anonymous

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Votes: -
DF = Fx*dx + Fy*dy or, dF/dx = Fx + Fy*dy/dx since, F(x,y) = 0 therefore, dF/dx = 0 or, Fx + Fy*dy/dx = 0 or, dy/dx = -Fx/Fy

Answer No.5

BrainyBrainy

From: US
Posts: 8
Votes: 24
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ? 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy hence proved

Answer No.6

TheGreatMonkey

From: US
Posts: 8
Votes: 16
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ? 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy HENCE PROVED

Answer No.7

Anonymous

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Posts: -
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DF = Fx*dx + Fy*dy =>F/dx = Fx + Fy*dy/dx but f(x,y)=0 so df/dx=0 =>Fx + Fy*dy/dx = 0 dy/dx = -Fx/Fy (proved)

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