EliteHead89 From: US Posts: 18 Votes: 18 |
Suppose y is a function of x, F(x,y) = 0, and Fy does not = 0. Show that dy/dx = - Fx/Fy |

iGenius From: US Posts: 3 Votes: 12 |
F(x,y) = 0 --> dF=0--> Fxdx+Fydy=0 --> Fxdx=-Fydy --> (dy/dx)=-Fx/Fy |

Anonymous From: - Posts: - Votes: - |
F(x,y) = 0 dF = 0 Fx dx + Fy dy = 0 Fxdx = - Fydy Since,Fy != 0 (dy/dx)=-Fx/Fy Hence,proved |

sam mayo From: US Posts: 15 Votes: 60 |
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ∴ 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy |

Anonymous From: - Posts: - Votes: - |
DF = Fx*dx + Fy*dy or, dF/dx = Fx + Fy*dy/dx since, F(x,y) = 0 therefore, dF/dx = 0 or, Fx + Fy*dy/dx = 0 or, dy/dx = -Fx/Fy |

BrainyBrainy From: US Posts: 8 Votes: 24 |
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ? 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy hence proved |

TheGreatMonkey From: US Posts: 8 Votes: 16 |
DF = Fx * dx + Fy * dy dF/dx = Fx + Fy*dy/dx F(x,y) = 0 ==> dF/dx = 0 ? 0=Fx + Fy*dy/dx and dy/dx = - Fx/Fy HENCE PROVED |

Anonymous From: - Posts: - Votes: - |
DF = Fx*dx + Fy*dy =>F/dx = Fx + Fy*dy/dx but f(x,y)=0 so df/dx=0 =>Fx + Fy*dy/dx = 0 dy/dx = -Fx/Fy (proved) |

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