Suppose F And G Are Functions That Are Differentia

Anonymous

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Suppose f and g are functions that are differentiable at x=1 and that f(1)=4, f(1)=-4, g(1)=-1, and g(1)=4. Find the value of h(1). h(x)=f(x)g(x) a. h(1)=-29 b. h(1)=20 c. h(1)=-8 d. h(1)=26

 

Answer No.1

Anonymous

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Given that h(x)=f(x)g(x) => h'(x)=f(x)g'(x)+f'(x)g(x) { product rule} => h'(1)=f(1)g'(1)+f'(1)g(1) =(4)(4)+(-4)(-1) =16+4=20

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