Question:With C An Arbitrary Constant, Find A Solu

Anonymous

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With C an arbitrary constant, find a solution to thedifferential equation given below: (secx)y'-cscy=0 NEED THIS ASAP!!! thanks so much.

 

Answer No.1

Anonymous

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(secx)y'-cscy=0 i.e, (secx)y' = cscy i.e (1/cosx)*[dy/dx] = 1/siny Seperating the variables we get sinydy = cosxdx Now, integrate on both sides -cosy = sinx + C or cosy = - sinx+c where c = -C ∴y = cos-1[-sinx +c]

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