If Y=e^(-x)ln(x) Then Dy/dx When X=1 Is ?

Anonymous

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If y=e^(-x)ln(x) then dy/dx when x=1 is ?

 

Answer No.1

Anonymous

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Use product rule, dy/dx = -e^(-x) ln x + e^(-x) 1/x -e^(-x) ln x + e^(-x)/x when x = 1, -e^(-1) ln 1 + e^(-1) / 1 since ln 1 = 0 1/e answer

Answer No.2

BigAsian73

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Dy/dx=1/x(e^-x)-e^-xlnx =e^-1(1-ln1) =e^-1

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