Anonymous From: - Posts: - Votes: - |
If an arrow is shot upward on the moon with a velocity of 58m/s, its height (in meters) after t seconds is given by H=58t -0.83t2 Find the velocity of the arrow after one second. |

Anonymous From: - Posts: - Votes: - |
H = 58t -0.83t2 tofind the velocity you have to take the derivative of theposition function H' = 58 -1.66t plug in 1 for t to find H'(1) H'(1) = 58 - 1.66(1) = 56.34m/s |

FrenchMary1 From: US Posts: 60 Votes: 120 |
Velocity is the derivative of H H'(t)=58-1.66t H'(1) = 58-1.66(1) The velocity after 1 second = 56.34m/s |

Anonymous From: - Posts: - Votes: - |
H(T)=58T-0.83T2 H'(T)=58-1.66T H'(1)=58-1.66(1) H'(1)=58-1.66 H'(1)=56.34METER/SECONDS |

JonnySam72 From: US Posts: 31 Votes: 93 |
H=58t - 0.83t2 <---This is our position function. The velocity function is simply thederivative of the position function. H(t) = 58t - 0.83t2 H'(t) = 58 - 1.66t Now we want to know what the velocity is after one second, so plugin one in the derivative: H'(1) = 58 - 1.66(1) H'(1) = 56.34 meters per second. |

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