WizAsian From: US Posts: 21 Votes: 42 |
Help me find the derivative: I know I must use the product rule first: y=(2x-5)^4(8x-5)^-3 the answer i got is not the same as in the book (btw, there is nothing on the solutions page on chegg for this...this is like the 4th problem, I've only had this for a few days and no one has answered any of my questions correctly so far...) please help! |

Anonymous From: - Posts: - Votes: - |
Y=(2x-5)^4(8x-5)^-3 y ' = (8 (2x-5)^3 (8x-5)^-3) - (24(8x-5)^-4 2x-5)^4) |

Anonymous From: - Posts: - Votes: - |
Y=(2x-5)^4(8x-5)^-3 Let (2x-5)^4 = a (8x-5)^-3 = b from product rule d(ab) = a db + b da ==> y' = (2x-5)^4 d ((8x-5)^-3) + (8x-5)^-3 d((2x-5)^4) = 8 (2x-5)^4 (8x-5)^-4 + 4(8x-5)^-3 (2x-5)^3 |

Anonymous From: - Posts: - Votes: - |
(2x-5)^4 * (-3) (8x-5)^-4 * 8 + 4(2x-5)^3 *2 *(8x-5)^-3 = 8*(2x-5)^3 *(8x-5)^-3 { -3(2x-5) /(8x-5) + 1} = 8 * (2x-5)^3 *(8x-5)^-4 * (-6x+15+8x-5) = 8 * (2x-5)^3 *(8x-5)^-4 * (2x+10) = 16 * (2x-5)^3 *(8x-5)^-4 * (x+5) |

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