Anonymous From: - Posts: - Votes: - |
Given: x2y2 - xy = 6 a. Use implicit differentiation to find the derivative with respectto x. b. Find a point on the curve where the tangent line is parallel tothe line y = x. Thanks for any help. |

TinyJay3 From: US Posts: 36 Votes: 108 |
A) x2y2 - xy = 6 2xy2 + 2x2 y y' - xy' - y = 0 => y' = (y-2xy2) / (2x2y - x) b) the line paralell to y=x have slop m = 1 let y' = 1 => (y-2xy2) / (2x2y - x) =1 y - 2xy2 = 2x2 y -x y+x = 2x2 y + 2xy2 = 2xy(x+y) => 2xy = 1 y = 1/2x let x = 1, y = 1/2 tangent line is: y = x +b 1/2 = 1 + b =>b=-1/2 y = x - 1/2 |

Anonymous From: - Posts: - Votes: - |
How canyou: let x = 1, y = 1/2 I'm not sure how you got to the next step: tangentline is: y = x +b 1/2 = 1+ b =>b=-1/2 y = x -1/2 |

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