Anonymous From: - Posts: - Votes: - |
G(m)= 8cos(m)/5 - 2cos(m2) is the derivative-- -8/5sin(m) + 4(m)sin(m2) ? Also, for h(n)= 6n/√3n2+1 How do I find thederivative of this one? So far I have(6n)(3n2+1)1/2 |

Anonymous From: - Posts: - Votes: - |
Your first derivative is correct, you used the chain rule correctlythere. For the second one, you need the product rule first. The solution follows, try not to look if you want to solve ityourself using the above hint :-) d/dx (6n * (3n^2 + 1)^(-1/2)) = d/dx (6n) * (3n^2 + 1)^(-1/2) + 6n * d/dx (3n^2 + 1)^(-1/2) = 6 * (3n^2 + 1)^(-1/2) + 6n * (-1/2) * (3n^2 + 1)^(-3/2) * d/dx(3n^2 + 1) = 6 * (3n^2 + 1)^(-1/2) + -3n * (3n^2 + 1)^(-3/2) * 6n = 6 * (3n^2 + 1)^(-1/2) + -18n^2 * (3n^2 + 1)^(-3/2) |

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