Find Y'' By Implicit Differentiation. 3x^3+4y^3 =1

EliteDan

From: US
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Find y'' by implicit differentiation. 3x^3+4y^3 =1

 

Answer No.1

LovelyJoe

From: US
Posts: 9
Votes: 36
3x^3+4y^3 =1 9x^2 + 12y^2 y' = 0 differentiate again 18x + 24y (y')^2 + 12y^2 y'' = 0

Answer No.2

Anonymous

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By using implicit diff, 9x^2 + 12y^2 dy/dx = 0 12y^2 dy/dx = -9x^2 dy/dx = -9x^2/12y^2 ==> -3x^2/4y^2 ans

Answer No.3

Anonymous

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3x^3+4y^3 =1 3*3x^2dx + 4*3y^2dy = 0 --- [1] dy = -3/4 (x^2 / y^2)dx dy/dx = -3/4 (x^2 / y^2) d^2y/dx^2 = -3/4 [y^2*2x - x^2*2y*dy/dx]/y^4 plug in the values

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