Samuel89jack From: US Posts: 37 Votes: 74 |
Find two positive integers such that the sum of the first numberand four times the second number is 1000 and the product of thenumbers is as large as possible. |

Anonymous From: - Posts: - Votes: - |
QuestionDetails: find two positive integers such that the sum of the first numberand four times the second number is 1000 and the product of thenumbers is as large as possible. LET THE 2 INTEGERS BE X AND Y X+4Y=1000 Z=XY SHOULD BE LARGEST Z=(1000-4Y)Y=-[4Y2-1000Y] = -[(2Y-250)-250*250] = 62500- (2Y-250)2.... HENCE Z WILL BE MAXIMUM WHEN 2Y=250...OR....Y=125 HENCE X=1000-4*125 = 500 SO THE 2 NUMBERS ARE 500 AND 125 |

Anonymous From: - Posts: - Votes: - |
Let them be x, and y x + 4y = 1000 =>y = (1000-x)/4 let f(x,y) = xy = f(x)=x[(1000-x)/4] = 250x -x2/4 f'(x) = 250 - x/2 = 0 => x = 500 y = (1000-500)/4 = 500/4 = 125 the two number is: 500,125 |

WizSam From: US Posts: 33 Votes: 99 |
Let the numbers be x & y. According to first condition: x + 4y = 1000--------------(1) According to second condition : xy = P-------------------(2) Put value of x from eqn (1) to eqn (2) (1000 - 4y) y = P ∴1000y - 4y2 = P Now, dP/dy = 1000 -8y For P to be maximum dP/dy = 0 ∴y = 125 & x =500 |

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