Find The Derivative Of The Functionf(x)= 1/7 X^7+(

Anonymous

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Find the derivative of the function f(x)= 1/7 x^7+(x^2+6)(x^2-x-6)+27 a. f(x)=7x3-15x-2 b. f(x)=x3+3x2+4 c. f(x)=4x6+7 d. f(x)=x6+4x3-3x2-6

 

Answer No.1

Anonymous

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You will need to know these formulas: (d/dx)(x^n) = nx^(n-1) (d/dx)(f(x) + g(x)) = f'(x) + g'(x) (d/dx)(f(x) - g(x)) = f'(x) - g'(x) (d/dx)(f(x)g(x)) = f'(x)g(x) + f(x)g'(x) f'(x) = (1/7)(7)x^6 + 2x(x^2 - x - 6) + (x^2 + 6)(2x - 1) = x^6 + 2x^3 - 2x^2 - 12x + 2x^3 - x^2 + 12x - 6 = x^6 + 4x^3 - 3x^2 - 6 which is d PLEASE RATE LIFESAVER if this helps you. THANKS.

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