Find The Curvature Of Y = Lnx At X = 1.

Anonymous

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Find the curvature of y = lnx at x = 1.

 

Answer No.1

Anonymous

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Y' = 1/x = 1 y" = -1/x^2 = -1 C = y"/(1 + y'^2)^3/2 = -1/(1+1)^3/2 = -1/22 = -0.354

Answer No.2

Anonymous

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F[x] = - Ln [x] df/dx =1/x d^2 f[x]/dx^2 = -1/x^2 And the curvature function is: -1/x^2/ ( 1+(1/x)^2 )^(3/2) at x = 1 gives = 1/2^3/2

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