Anonymous From: - Posts: - Votes: - |
Find f'(x) given that f(x)= 15/(4+ln(7x)) what is the domain? |

MathTeacher From: US Posts: 3 Votes: 3 |
F(x)= 15/(4+ln(7x)) f'(x) = -15*7*(1/7x)/(4+ln(7x)^2 = -15/(x(4 + ln(7x))^2 4 + ln(7x) = 0 Therefore x = e-4/7 = 2.6*10^-3 Therefore Domain is all real no. except x = 0 , 2.6*10^-3 |

Anonymous From: - Posts: - Votes: - |
F'(x) = -15/((4+ln(7x))^2 *(7/x) = -105/(x*((4+ln(7x))^2) to find domain 7x > 0 => x>0 4+ln(7x) must be non 0 => ln(7x) should be not equal to -4 => x should be not equal to (e^-4)/7 so domain is x>0 and x not equal to (e^-4)/7 |

Anonymous From: - Posts: - Votes: - |
F'(x) = -15/((4+ln(7x))^2 *(7/x) = -105/(x*((4+ln(7x))^2) to find domain 7x > 0 => x>0 4+ln(7x) must be non 0 => ln(7x) should be not equal to -4 => x should be not equal to (e^-4)/7 so domain is x>0 and x not equal to (e^-4)/7 |

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