Find F'(x) Given That F(x)= 15/(4+ln(7x)) And Stat

Anonymous

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Find f'(x) given that f(x)= 15/(4+ln(7x)) and state it domain in interval notation

 

Answer No.1

MythSam

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F(x)= 15/(4+ln(7x)) f'(x) = [ -15 ( 1/7x)7 ] / (4+ln(7x))^2 = - 15/(4+ln(7x)) ^2 domain D = x>0

Answer No.2

Anonymous

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F(x)= 15/(4+ln(7x)) f'(x)= (15/7x)ln(4+ln(7x)) (4+ln(7x))>0 7x>e^-4 x>(e^-4)/7 x=((e^-4)/7,infinity)

Answer No.3

Anonymous

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F'(x)=1(1/7x)/(4+ln(7x))^2=1/7x(4+ln(7x))^2 domain 4+ln(7x)>0 4+ln(7x)<0 x=-e^-4/7 [-infi ,-e^-4/7] [-e^-4/7, iinfi]

Answer No.4

Anonymous

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F(x)= 15/(4+ln(7x)) f'(x) = [ -15 ( 1/7x)] / (4+ln(7x))^2 = - 15/7x(4+ln(7x)) ^2 7x(4+ln(7x)) ^2=0 x=0, 7x>0 x>0 (4+ln(7x)) ^2=0 x=(e^-4)/7 domain x=(0,infinity)-(e^-4)/7

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