Find An Equation Of The Tangent Line To The Graph

Anonymous

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Find an equation of the tangent line to the graph of the function at the point (1,1). F(x)= (2-x)(x2-2)2 a. y= 21x+6 b. y=-5x-40 c. y=-5x+6 d. y=21x-40

 

Answer No.1

Anonymous

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Derivative of F(x) is slope of tangent line: Since F(x) = -x^5 + 2x^4 + 4x^3 - 8x^2 - 4x + 8, F'(x) = -5x^4 + 8x^3 + 12x^2 - 16x - 4 F'(1) = -5 + 8 + 12 - 16 - 4 = -5. Therefore, equation of tangent line is y = -5(x-1) + 1 = -5x+6 Which is answer c.

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